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Alberto Donizetti authored
There are a few cases where this can be useful. Apart from the obvious (and silly) 100*n + 200*n where we generate one IMUL instead of two, consider: 15*n + 31*n Currently, the compiler strength-reduces both imuls, generating: 0x0000 00000 MOVQ "".n+8(SP), AX 0x0005 00005 MOVQ AX, CX 0x0008 00008 SHLQ $4, AX 0x000c 00012 SUBQ CX, AX 0x000f 00015 MOVQ CX, DX 0x0012 00018 SHLQ $5, CX 0x0016 00022 SUBQ DX, CX 0x0019 00025 ADDQ CX, AX 0x001c 00028 MOVQ AX, "".~r1+16(SP) 0x0021 00033 RET But combining the imuls is both faster and shorter: 0x0000 00000 MOVQ "".n+8(SP), AX 0x0005 00005 IMULQ $46, AX 0x0009 00009 MOVQ AX, "".~r1+16(SP) 0x000e 00014 RET even without strength-reduction. Moreover, consider: 5*n + 7*(n+1) + 11*(n+2) We already have a rule that rewrites 7(n+1) into 7n+7, so the generated code (without imuls merging) looks like this: 0x0000 00000 MOVQ "".n+8(SP), AX 0x0005 00005 LEAQ (AX)(AX*4), CX 0x0009 00009 MOVQ AX, DX 0x000c 00012 NEGQ AX 0x000f 00015 LEAQ (AX)(DX*8), AX 0x0013 00019 ADDQ CX, AX 0x0016 00022 LEAQ (DX)(CX*2), CX 0x001a 00026 LEAQ 29(AX)(CX*1), AX 0x001f 00031 MOVQ AX, "".~r1+16(SP) But with imuls merging, the 5n, 7n and 11n factors get merged, and the generated code looks like this: 0x0000 00000 MOVQ "".n+8(SP), AX 0x0005 00005 IMULQ $23, AX 0x0009 00009 ADDQ $29, AX 0x000d 00013 MOVQ AX, "".~r1+16(SP) 0x0012 00018 RET Which is both faster and shorter; that's also the exact same code that clang and the intel c compiler generate for the above expression. Change-Id: Ib4d5503f05d2f2efe31a1be14e2fe6cac33730a9 Reviewed-on: https://go-review.googlesource.com/55143Reviewed-by: Keith Randall <khr@golang.org>
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