Commit 44fe90d0 authored by Rick Hudson's avatar Rick Hudson

[dev.garbage] runtime: logic that uses count trailing zero (ctz)

Most (all?) processors that Go supports supply a hardware
instruction that takes a byte and returns the number
of zeros trailing the first 1 encountered, or 8
if no ones are found. This is the index within the
byte of the first 1 encountered. CTZ should improve the
performance of the nextFreeIndex function.

Since nextFreeIndex wants the next unmarked (0) bit
a bit-wise complement is needed before calling ctz.
Furthermore unmarked bits associated with previously
allocated objects need to be ignored. Instead of writing
a 1 as we allocate the code masks all bits less than the
freeindex after loading the byte.

While this CL does not actual execute a CTZ instruction
it supplies a ctz function with the appropiate signature
along with the logic to execute it.

Change-Id: I5c55ce0ed48ca22c21c4dd9f969b0819b4eadaa7
Reviewed-on: https://go-review.googlesource.com/20169Reviewed-by: 's avatarKeith Randall <khr@golang.org>
Reviewed-by: 's avatarAustin Clements <austin@google.com>
parent e4ac2d4a
......@@ -186,12 +186,22 @@ func (s *mspan) allocBitsForIndex(allocBitIndex uintptr) markBits {
return markBits{&s.allocBits[whichByte], uint8(1 << whichBit), allocBitIndex}
}
// A temporary stand in for the count trailing zero ctz instruction.
func ctz(markBits byte) uint8 {
tz := uint8(0) // trailing zero count.
if markBits == 0 {
return 8 // 8
}
for mask := byte(1); mask&markBits == 0; mask, tz = mask<<1, tz+1 {
}
return tz
}
// nextFreeIndex returns the index of the next free object in s at or
// after the index'th object.
// There are hardware instructions that can be used to make this
// faster if profiling warrants it.
func (s *mspan) nextFreeIndex(index uintptr) uintptr {
var mask uint8
if index == s.nelems {
return index
}
......@@ -200,47 +210,34 @@ func (s *mspan) nextFreeIndex(index uintptr) uintptr {
}
whichByte := index / 8
theByte := s.allocBits[whichByte]
// Optimize for the first byte holding a free object.
if theByte != 0xff {
mask = 1 << (index % 8)
for index < s.nelems {
if mask&theByte == 0 {
return index
}
if mask == 1<<7 {
break
}
mask = mask << 1
index++
}
}
maxByteIndex := (s.nelems - 1) / 8
theByte = 0xff // Free bit not found in this byte above so set to 0xff.
// If there was a 0 bit before incoming index then the byte would not be 0xff.
for theByte == 0xff {
whichByte++
if whichByte > maxByteIndex {
return s.nelems
}
if uintptr(len(s.allocBits)) <= whichByte {
throw("whichByte > len(s.allocBits")
}
theByte = s.allocBits[whichByte]
}
index = whichByte * 8
mask = uint8(1)
for index < s.nelems {
if mask&theByte == 0 {
return index
theBitMask := uint8(1<<(index%8) - 1)
// theBitMask holds a 1 for every bit < index which have already been allocated.
// Flip the masked marked bits so 1 means a free bit.
theByte = ^(theByte | theBitMask)
tz := ctz(theByte)
if tz != 8 {
result := uintptr(tz) + whichByte*8
if result >= s.nelems {
return s.nelems
}
if mask == 1<<7 {
break
return result
}
whichByte++
index = (whichByte) * 8
for ; index < s.nelems; index += 8 {
theByte = ^s.allocBits[whichByte]
tz = ctz(theByte)
if tz != 8 {
result := uintptr(tz) + whichByte*8
if result >= s.nelems {
return s.nelems
}
return result
}
mask = mask << 1
index++
whichByte++
}
return index
return s.nelems
}
func (s *mspan) isFree(index uintptr) bool {
......
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