-
Daniel Martí authored
In hasSideEffects, vet has to be taught whether or not a CallExpr is an actual function call, or just a type conversion. The previous code knew how to differentiate fn(arg) from int(arg), but it incorrectly saw (func(T))(fn) as a func call. This edge case is slightly tricky, since the CallExpr.Fun has a func signature type, just like in func calls. However, the difference is that in this case the Fun is a type, not a value. This information is in types.TypeAndValue, so use it. Change-Id: I18bb8b23abbe7decc558b726ff2dc31fae2f13d6 Reviewed-on: https://go-review.googlesource.com/111416 Run-TryBot: Daniel Martí <mvdan@mvdan.cc> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by:
Robert Griesemer <gri@golang.org>
3fbfc83d