Commit 73f11171 authored by Adam Langley's avatar Adam Langley

math/big: add 4-bit, fixed window exponentiation.

A 4-bit window is convenient because 4 divides both 32 and 64,
therefore we never have a window spanning words of the exponent.
Additionaly, the benefit of a 5-bit window is only 2.6% at 1024-bits
and 3.3% at 2048-bits.

This code is still not constant time, however.

benchmark                        old ns/op    new ns/op    delta
BenchmarkRSA2048Decrypt           17108590     11180370  -34.65%
Benchmark3PrimeRSA2048Decrypt     13003720      7680390  -40.94%

R=gri
CC=golang-dev
https://golang.org/cl/6716048
parent ace9ff45
......@@ -1248,6 +1248,15 @@ func (z nat) expNN(x, y, m nat) nat {
}
z = z.set(x)
// If the base is non-trivial and the exponent is large, we use
// 4-bit, windowed exponentiation. This involves precomputing 14 values
// (x^2...x^15) but then reduces the number of multiply-reduces by a
// third. Even for a 32-bit exponent, this reduces the number of
// operations.
if len(x) > 1 && len(y) > 1 && len(m) > 0 {
return z.expNNWindowed(x, y, m)
}
v := y[len(y)-1] // v > 0 because y is normalized and y > 0
shift := leadingZeros(v) + 1
v <<= shift
......@@ -1304,6 +1313,69 @@ func (z nat) expNN(x, y, m nat) nat {
return z.norm()
}
// expNNWindowed calculates x**y mod m using a fixed, 4-bit window.
func (z nat) expNNWindowed(x, y, m nat) nat {
// zz and r are used to avoid allocating in mul and div as otherwise
// the arguments would alias.
var zz, r nat
const n = 4
// powers[i] contains x^i.
var powers [1 << n]nat
powers[0] = natOne
powers[1] = x
for i := 2; i < 1<<n; i += 2 {
p2, p, p1 := &powers[i/2], &powers[i], &powers[i+1]
*p = p.mul(*p2, *p2)
zz, r = zz.div(r, *p, m)
*p, r = r, *p
*p1 = p1.mul(*p, x)
zz, r = zz.div(r, *p1, m)
*p1, r = r, *p1
}
z = z.setWord(1)
for i := len(y) - 1; i >= 0; i-- {
yi := y[i]
for j := 0; j < _W; j += n {
if i != len(y)-1 || j != 0 {
// Unrolled loop for significant performance
// gain. Use go test -bench=".*" in crypto/rsa
// to check performance before making changes.
zz = zz.mul(z, z)
zz, z = z, zz
zz, r = zz.div(r, z, m)
z, r = r, z
zz = zz.mul(z, z)
zz, z = z, zz
zz, r = zz.div(r, z, m)
z, r = r, z
zz = zz.mul(z, z)
zz, z = z, zz
zz, r = zz.div(r, z, m)
z, r = r, z
zz = zz.mul(z, z)
zz, z = z, zz
zz, r = zz.div(r, z, m)
z, r = r, z
}
zz = zz.mul(z, powers[yi>>(_W-n)])
zz, z = z, zz
zz, r = zz.div(r, z, m)
z, r = r, z
yi <<= n
}
}
return z.norm()
}
// probablyPrime performs reps Miller-Rabin tests to check whether n is prime.
// If it returns true, n is prime with probability 1 - 1/4^reps.
// If it returns false, n is not prime.
......
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